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Having no luck using a Python script to select files http://classicshell.net/forum/viewtopic.php?f=8&t=8507 |
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Author: | mdsy [ Wed Jan 09, 2019 6:49 pm ] |
Post subject: | Having no luck using a Python script to select files |
Having no luck using a Python script to select files in Explorer, although I have achieved the same thing an EXE (written in C#) but cannot get the Python script to execute: the C# EXE command: Code: "F:\[Source]\[Classic Shell Assistants]\Select Files\Select same name\SelSameName.exe" "%5" "%2" and the Python script Code: "F:\[Source]\[Classic Shell Assistants]\Select Files\Select same name\SelSameName.py" "%5" "%2" Is there something I should change in the command ? Just for completeness, here are the contents of the script which works when I run it manually and feed it the required arguments: Code: import glob, re, sys, os.path
def main(args): if len(args) == 2: out_file = args[0]; sel_file = args[1]; dirname, sel_file = os.path.split(sel_file) sel_file, _ = os.path.splitext(sel_file) #print(sel_file) rx = re.compile(r"[a-z 0-9]+", re.IGNORECASE); m = rx.match(sel_file) #print(m) s = m.group().strip() print(s) #var files = Directory.GetFileSystemEntries(dir, s + "*.*"); #files = os.listdir(dirname) files = glob.glob( os.path.join(dirname, s) + "*.*", recursive=False) #print(files) sb = ['Select'] for file in files: _ , fname = os.path.split(file) sb.append(fname) ss = '\n'.join(sb) #print(ss) with open(out_file, "w", encoding="utf-8") as f: f.write(ss) #just for testing with open('f:/logz.txt', "w", encoding="utf-8") as f: try: f.write(str(len(sys.argv)) + '\n') f.write(str(sys.argv) + '\n') f.write(__file__) except Exception as ex: print(ex) main(sys.argv[1:]) |
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